[Loose Screw]

With all the talk about canburglars OP, I want to check the math to see if it's possible to win a 1-3 RC loss at very high competitive play. Assuming auto points to be equal, and both alliances can make 42pt stacks with every container they have.

Alliance 1: 3RC grab auto
6*42+4*4=268

Alliance 2: 1RC grab auto
4*42+4*6=192

268-192=76, an additional 38 totes must be scored. With 4*6 totes being used by RC stacks, that leaves only 24 totes left to be scored. With auto points being matched, it is impossible to win at this insane level.

Now if Alliance 2 had a perfect 32pt auto mode, it would make it closer.

Alliance 1: 6*42+4*4=268

Alliance 2: 4*42+4*6+32=224

268-224=44, meaning 22 additional totes need to be scored to match scores.

So, in theory, it is possible to win, but highly unlikely. In this scenario where Alliance 1 can score 6 42pt stacks (wow!), it is highly likely that they also have a good autonomous mode score.

If an alliance in Finals steals 3 or 4 containers (and be able to score them), there is nothing Alliance 2 can do to win. It is very possible that two top teams could score 3 42pt stacks independantly, meaning that this scenario is very much possible.

TL;DR: RCs OP