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Unread 27-05-2015, 10:05
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Ether Ether is offline
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Re: about the torque calculation of a mecanum wheel

Quote:
Originally Posted by GeeTwo View Post
While Matsinos does decompose the "driving force" Fi into Fi,p and Fi,t improperly because he assumes that it is transverse to the wheel axis (it is not), this error is inconsequential
His error is fundamental.

He takes a component of force (Fi), breaks it into 2 new components (Fi,p and Fi,t), throws away one of those components (Fi,t), and then breaks the remaining component (Fi,p) into yet two new components (Fi,y and Fi,x).

This is a common high-school physics error.

The proper way to analyze the wheel is to start with the net force (of the floor acting on the bottom of the wheel, in the plane of the floor). This net force Fi,net has a known direction: parallel to the axis of the roller touching the floor.

Then break that net force Fi,net into forward Fi,y and sideways Fi,x components.

The forward force Fi,y will be equal to tau/r, where tau is the driving torque on the wheel and r is the wheel radius. This known value of Fi,y can then be used to compute the magnitude of Fi,x and Fi,net.



Last edited by Ether : 27-05-2015 at 10:48.