[nardavin]

It seems that there are far fewer combinations possible, given the multiple rules that define how the obstacles can be chosen. Here is my math:

4(Position of groups A,B,C,D) * 1(Red position 1: low bar) * 2(Red position 2) * 2(Red position 3 - chosen by audience) * 2(Red position 4) * 2(Red position 5) * 1(Blue position 1 - low bar) * 2(Blue position 2) * 1(Blue position 3 - same as Red 3) * 2(Blue position 4) * 2(Blue position 5)

4*1*2*2*2*2*1*2*1*2*2 = 512

That seems awfully small, and way off of the game manual's 14000 (IIRC) advertised positions. Am I doing something wrong, or was the 14000 calculated without some of the rules in mind?