Quote:
Originally Posted by Ether
Here's a quick calculation using MCALC to compare
one CIM drawing 60 amps at 12 volts
vs
two CIMs each drawing 30 amps at 12 volts:
Code:
Motor Calculator build MCALC_2014d 2/3/2014 1255pm
Select motor:
1)CIM 6)FP0673 d)FP2719 f)FP9012 g)FP9015 h)FP9013 j)MiniCIM
a)am-0912 b)am-0914 7)DensoL 8)DensoR c)Denso0160 k)BAG u)UserDefined
2)RS395 3)RS540 4)RS550 e)RS775-12 5)RS775-18 m)RS555 n)am-0915
r)am-2193 s)am-2235 t)RS390 v)RS545 p)am-2161&2194
w)VEX2177hi z)VEX2177std 1
CIM FR801 001, AM802 001A @ 12.00 volts:
@ free (no load):
oz-in Nm rpm rpm% amps watts out watts heat eff%
0.0 0.000 5310 100.0 2.7 0.0 32.4 0.0
@ stall:
oz-in Nm rpm rpm% amps watts out watts heat eff%
343.4 2.425 0 0.0 133.0 0.0 1596.0 0.0
@ max power:
oz-in Nm rpm rpm% amps watts out watts heat eff%
171.7 1.212 2655 50.0 67.8 337.1 477.1 41.4
@ max efficiency:
oz-in Nm rpm rpm% amps watts out watts heat eff%
42.8 0.302 4648 87.5 18.9 147.1 80.2 64.7
Select input:
1)oz-in 7)watts_in 3)rpm 5)amps b)rpm&s 8)eff%
2)Nm 6)watts_out 4)rpm% 9)volts a)rpm&ozin m)main menu x)exit 5
enter amps: 60
CIM FR801 001, AM802 001A @ 12.00 volts:
oz-in Nm rpm rpm% amps watts out watts heat eff%
151.0 1.066 2975 56.0 60.0 332.2 387.8 46.1
Select motor:
1)CIM 6)FP0673 d)FP2719 f)FP9012 g)FP9015 h)FP9013 j)MiniCIM
a)am-0912 b)am-0914 7)DensoL 8)DensoR c)Denso0160 k)BAG u)UserDefined
2)RS395 3)RS540 4)RS550 e)RS775-12 5)RS775-18 m)RS555 n)am-0915
r)am-2193 s)am-2235 t)RS390 v)RS545 p)am-2161&2194
w)VEX2177hi z)VEX2177std u
Enter the following motor specs in the order and units indicated,
separated by spaces or tabs:
volts stall_ozin free_rpm stall_amps free_amps
12 686.8 5310 266 5.4
UserDefined-> 12.0 686.8 5310 266.0 5.4 @ 12.00 volts:
@ free (no load):
oz-in Nm rpm rpm% amps watts out watts heat eff%
0.0 0.000 5310 100.0 5.4 0.0 64.8 0.0
@ stall:
oz-in Nm rpm rpm% amps watts out watts heat eff%
686.8 4.850 0 0.0 266.0 0.0 3192.0 0.0
@ max power:
oz-in Nm rpm rpm% amps watts out watts heat eff%
343.4 2.425 2655 50.0 135.7 674.2 954.2 41.4
@ max efficiency:
oz-in Nm rpm rpm% amps watts out watts heat eff%
85.6 0.605 4648 87.5 37.9 294.3 160.4 64.7
Select input:
1)oz-in 7)watts_in 3)rpm 5)amps b)rpm&s 8)eff%
2)Nm 6)watts_out 4)rpm% 9)volts a)rpm&ozin m)main menu x)exit 5
enter amps: 60
UserDefined-> 12.0 686.8 5310 266.0 5.4 @ 12.00 volts:
oz-in Nm rpm rpm% amps watts out watts heat eff%
143.9 1.016 4197 79.0 60.0 446.6 273.4 62.0
one CIM drawing 60 amps at 12 volts:
332 watts output mechanical power
388 watts waste heat
two CIMs each drawing 30 amps at 12 volts:
447 watts output mechanical power
273 watts waste heat
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Wouldnt a 1/4 hp motor and a 1/2 hp motor consume the same amount of power if the continuous load only required 1/8 hp. Amperage being based on load.
I know that 2 cims will be capable of more torque, I'm just wondering how noticeable it will be from the perspective of the driver.