[ATannahill]

Originally Posted by Bkeeneykid

I decided to work on a 6 alliance elimination schedule. This is probably a crazy idea, but it'll probably work.

Match    Blue   Red
TF1       1        6
TF2       2        5
TF3       3        4

SF1       TF1    TF2
SF2       TF1    TF3
SF3       TF2    TF3

F          SF1     SF3

(repeat each match, then do tie breakers, like normal eliminations)

To explain this, the Tri-Finals (for lack of a better name) would be the equivalent of the current Quarters. The Semi-Finals is where it gets weird. The winners of each Tri-final go on to do two matches (Technically 4-6, with tiebreakers). If they win both semi-finals, they go onto regular finals, proceeding like normal finals. If they loose one of them, they'll replay the match between the two (again, with second round & tiebreaker). Then that winning alliance goes onto regular finals.

With only six alliances, there's a potential maximum of 27 rounds for eliminations, assuming each round goes to a tiebreaker. There's a minimum of 14, so I could see the wide variety of times to plan for an issue. But it proves that six alliance playoffs are possible.

EDIT: Made a quick flowchart of how this proposed flow would go:

I am confused how you get your two finalists, can you explain it again?

As I understand each round proceeds normally, there are two matches played, if each match goes to a different alliance than a third is played hopefully generating a winner. The winner of the TF1 round moves on, the winner of the TF2 round moves on and the winner of the TF3 moves on.

I do not understand how you narrow down from the three Tri-final winners to the two finalists.

Edit: The flowchart makes it easier to understand, I would suggest switching the names of SF2 and SF3. How do you even out the fact that TF2 has played twice as many matches as TF1 or TF3 if SF2(3) is not needed?