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Re: Statistics/Probability Quiz
I'm gonna try this one:
Here goes my logic:
Let's say we order the 420 rolls and first require that they be in the exact order of 70 1's first, 70 2's second, etc.
Then, the probability of getting this exact order is (1/6)^420
Now, let's say we start flip-flopping these around, with a specific rule: you can only switch with a number later in the sequence that isn't the same as the one you already have. This takes care of duplicate scenarios. So, for the 1's, you can flip each one with 420-70 = 350 different positions.
The way to calculate that would be:
(1/6)^70 *(420-1*70) +
(1/6)^70 *(420-2*70) +
...
(1/6)^70 *(420-6*70) = 3.55*10^(-52)
The 70 exponents are because each group of 70 has that chance of being picked that way.
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