[jon virgi]

your einstein + pythagoras does not work. c in the einstein equation is the speed of light (constant )(3x10^8). Einsteins equation can be used to calculate stuff like bond energies and crap like that in MeV (mega electron volts).

now with the limit you posted , Lim n->infinity (sin(x))\n = 0, and not 6. there's no n in numerator, so denominator gets infinitely large, hence, it equals 0.

If you had something like Lim x->0 (sin(x))/x , then the answer is 1. since lim x->0 sinx/x = 0/0 , then we can use L'Hopitals rule, take derivative, get Lim x->0 (cos(x))/1 = 1/1=1

I put that in case u were unsure of limits, b/c the one u gave did not make sense.