Quote:
Originally Posted by Monochron
are you still able to hit peak power with this given ratio at each voltage? My question is really, is the ratio needed for peak power at 12V the same ratio needed for peak power at 6V?
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Suppose you have a motor whose free speed is 6000 rpm at 12 volts when connected 1:1 with an unloaded flywheel.
Suppose your desired flywheel operating speed is 3000 rpm.
For the sake of simplicity, ignore parasitic losses and say it takes 6 volts to keep the motor (and flywheel) running at the desired 3000 rpm when the flywheel is unloaded.
If you have 12 volts available, you can get max power output from the motor (to respond to a load being applied to the flywheel) by changing the motor voltage from 6 volts to 12 volts.
But if all you have available is 6 volts (because of weak battery and heavy current draw elsewhere), then you cannot supply
any additional power to the motor at 3000 rpm.