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Re: Velocity Control - Battery Compensation Term
Quote:
Originally Posted by Ether
Here's a rough calculation:
10000 rpm motor free speed at 100% command
6500 rpm motor free speed at 65% command
2500 desired operating rpm of flywheel
2.6:1 speed reduction gear ratio = 6500/2500
YMMV depending on how much friction and windage you have in your gearing and flywheel
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This ^ with a 0.8-0.9 for gearbox efficiency will get you close. For this example, 65% command: 10,000 rpm * 0.65 * 0.8 = 5200 rpm free speed. 5200/2500 yields approx 2:1 gear ratio.
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