Quote:
|
Originally Posted by Matt Adams
2. In which direction is this force applied? As for direction, I assume a significant amount of the force is pushing them directly tangent to where the teeth mesh, but I think this is this too much of a simplification. Is the direction actually related to the gears' pressure angle? What about with mutiple teeth engaging? This seems like it could develop into a rather complex problem...
I'll guess it's something like (T / (D/2))*SIN(PA) is the force pushing them apart in the plane of the shaft centers... but I'd really appreciate it if someone had something better than a guess. 
Thanks in advance,
Matt |
Matt,
The force between the gears acts along the line of pressure. This line is determined by the pressure angle.
Therefore, you are correct with your formula.
-Chris