[Adam Shapiro]

Originally Posted by Just3D

Notice the ampherstand (&). This will tell printf to read the value of pwn02 rather than the memory address of pwn02

Correct me if I'm wrong but from my knowledge of C syntax and printf() the & would cause printf() to read the address of the variable, not the value. If you are working with a pointer (which you are not in this case) you would use * to access the value, not &. Unless in a function declaration (or in a binary/logic statement) & always references the address of a variable.

Still, I could be wrong with the C18-based printf() library, you never know...