Thread: .999~ = 1
View Single Post
  #18   Spotlight this post!  
Unread 26-01-2004, 11:16
Kris Verdeyen's Avatar
Kris Verdeyen Kris Verdeyen is offline
LSR Emcee/Alamo Game Announcer
FRC #0118 (Robonauts)
Team Role: Engineer
 
Join Date: Jun 2001
Rookie Year: 2001
Location: Houston, TX
Posts: 699
Kris Verdeyen has a reputation beyond reputeKris Verdeyen has a reputation beyond reputeKris Verdeyen has a reputation beyond reputeKris Verdeyen has a reputation beyond reputeKris Verdeyen has a reputation beyond reputeKris Verdeyen has a reputation beyond reputeKris Verdeyen has a reputation beyond reputeKris Verdeyen has a reputation beyond reputeKris Verdeyen has a reputation beyond reputeKris Verdeyen has a reputation beyond reputeKris Verdeyen has a reputation beyond repute
Re: .999~ = 1

Quote:
Originally Posted by n00b
major probelm: you cannot take the ln of a negative number. therefore, the term ln e^(i * pi) cannot exist. i have another one of those phony proofs, its kinda fun:

let a=1, b=1
a = a
a^2 = ab
a^2 - b^2 = ab - b^2
(a + b)(a - b) = b(a - b)
a + b = b
1 + 1 = 1

have fun =D
Although, I think it would actually go like this:
let a=1, b=1
a = a
a^2 = ab
a^2 - b^2 = ab - b^2
(a + b)(a - b) = b(a - b)

This line gives you a division by zero error when you divide both sides by (a-b), because a-b = 0.

Also, e^i*pi is a perfectly valid expression that doesn't take the ln of a negative number. e^i*pi = cos(pi) + i sin(pi) = -1
__________________
...Only a few people are awake and they live in a state of constant total amazement. -JP Shanley, Joe vs. the Volcano

Last edited by Kris Verdeyen : 26-01-2004 at 11:20.
Reply With Quote