[KenWittlief]

the current in the motor leads will be twice the current in the supply leads?!

where do you think the motor leads are getting that current from?

all the victor does is pulse width modulate the supply, when you are going slow it pulses the output on for a short period, then switches it back off for a longer period - full on, full off.

the victor does not have anyway to store up energy, so the current on the output side is = the current on the input side, minus the slight amount the victor uses (or wastes due to it not being 100% effecient)

Thats what I think they were getting at in '99, you might get an extra half amp out of the breaker if its on the output side

but there was a tiny little problem with doing that. When the victors fail they often short internally, +12V right to ground - so if you have a chip of metal fall into it, and the breaker is on the output side, the only thing protecting the victor is the main breaker - which can source enough current to turn the victor into a pyrotechnic display, including the 10 gauge wire that is feeding it.

Which is why its no longer legal - many victors went up in smoke that year.