Quote:
|
Originally Posted by Kevin Sevcik
P1*V1=P2*V2. And I'm ignoring the volume of the tubes, as it is relatively negligible at this scale.
|
The equation is right, but you forgot the accumulators are at 120psi. I'm also not sure about your volume calculations. I thought the accumulators are 2" bore x 6" long, which gives 18.8 in^3. I could be wrong, but the answer won't be terribly different if they are 16 in^3
You use 14.1 in^3 (at 60 PSI) when you actuate the cylinder. The accumulators hold 37.6 in^3 (at 120 PSI). Since you are only using the air at 60 PSI, you effectively have 75.2 in^3 of air, and when you get down to 37.6 in^3, you will only have 60 PSI. Thus, you have 37.6 in^3 of air to work and can actuate the cylinder twice. If you can regulate the cylinder to 50 PSI, you could get 3 shots.