[patrickrd]

Joe,

Thanks for the analysis! The "dutch pin" I had heard from other teams over the past couple years was actually the second example you listed, but I think I like the the first example even better. I think the stress in the second example would be very difficult to calculate... However the fact is that with your example you are distributing the force over a much greater area than with any other type of pin -- so I think that will be best even though shear yield is typically about half of normal yield.

Thanks,
Patrick

Originally posted by Joe Johnson
I am not sure what you mean by a "dutch pin" because there is some confusion on this subject in my mind.

If I understand it correctly, you drill a hole that is parallel to the axis of rotation and is centered on the circle that is interface between the driver member and the driven member.

I have also heard a hole that is 90 degrees from axis of rotation but offset the same amount so that the center of the pin is tangent to the cylinder that is the interface between the driver member and the driven member.