Quote:
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Originally Posted by Daniel
If you read the file "printf_lib.c" (I think) you will see a comment that says "%c" is not supported. The best you are going to do is put the character into a char array two long setting your character in location 0 and '\0' (or zer0) in location 1, then print it using "%s" as the format and using the array name.
char t [2];
t [0] = 61; // Or what ever you character is.
t [1] = '\0' // Null character.
printf ("%s\n", t);
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yeah, try that... forgot about the null terminator, because i'm so used to just using strcpy
gotten lax.