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Originally Posted by CrazyCarl461
They should attract with a force equal to (u0*L*ia*ib)/(2*pi*d). If L is a length vector in the direction of current flow, there must be a perpendicular B vector which means L cross B results in a force that is also perpendicular with the wire. Is that right? PHYS241 was not one of my favorites.
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Crazy's right, but you still need to know the mass of the rods!