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Re: Odd Escape
Well...I think I've got the paper solution to the first one...
Given that there are 3 doors and 1 of them is "escape", you can:
A) Choose door 1
B) Choose door 2
C) Choose door 3
Now given that 3 is the "correct" door, if you pick 1, 2 will be taken away and vice versa and if you pick 3, either 1 or 2 will be taken away.
A1) Stick with door 1
A2) Go with door 3
B1) Stick with door 2
B2) Go with door 3
C1) Stick with door 3
C2) Change to door 1 or 2 (whichever is not eliminated)
Now, as you can see, if you stick with your first choice (A1, B1, C1), you have a 1 in 3 chance (C1) of getting it correct while if you change it (A2, B2, C2) you have a 2 in 3 chance of getting it right (A2, B2).
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