[Al Skierkiewicz]

The current generated by pushing can only go where there is a complete circuit. The current flows backward through the resistances of the FETs, this is what lights the LEDs and turns the fans but the current will flow through anything that is connected together through the fuse panel which is connected to the power input of the victors. There is a direct relation to the amount of current passing through circuitry and the force it takes to push the robot. Push harder and more current flows. Since heat is work and work is measured in watts, and watts equals volts times amps...then yes as long as you push and make a voltage that generates current it will develop heat. Although the heat is small, it is generated in any part of the circuit that has resistance. Namely, LEDs, wire, other motors (fans), the victors and the RC will be where the current flows through resistance and heat is generated.
It is possible to connect two motors together and while turning just one of them, the current generated will turn the other one. Since the conversion process of turning the motor to generate electricity and using the electricity to make another motor turn, is a lossy one, the first motor must turn faster than the second one. These efficiencies are rarely above 96% and if you compare the efficiency curves of the motors you can get an idea of what speeds will produce the optimum results but it can be done. What work doesn't convert to mechanical energy at the other end is given up as heat in the two motor's windings. If you try this at home, test how hard it is to turn a motor that is not connected to anything and then connect the two and try the same motor to see if there is a difference. Report back, inquiring minds want to know.