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Originally Posted by Al Skierkiewicz
Don't forget that there are three FETs in parallel, .012/3=.004 or about the resistance of four feet of #10.
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Wouldn't it be three FETs in parallel sourcing current plus three FETs in parallel drawing current, and hence 0.008 Ω? It's an H-Bridge after all, isn't it?
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Originally Posted by KVermilion
Hey guys. During the winter break I was working on the current sensors... I came across this post and decided to check it out for my self... I wired up the current sensors and graphed some points (all of them.. twice) and the results are astonishing.
I'm writing it up now, and will publish it via our site ( www.saratogarobotics.com) I'll post back with a link, when I'm done.
Here you go.
Wrote this tonight too... interesting, no? |
Interesting data, just be aware when comparing your results with Rickertsen2's that you used a resistor and he used a motor (resistor + voltage source + inductor model). Of course, your tests are better, because this resistor setup will not interfere with the Victor's output waveform.
With your data, we can say for sure that the Victor's are linear (something the IFI guys already told us, for the matter), I'm just a little puzzled about the current "crop" at the graphic's extremes, were you using a battery to feed the Victor or maybe a different power supply with a maximum output current?