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Originally Posted by Kevin Sevcik
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thank you, that site was incredibly informative. I worked this out:
i can solve the voltage difference between my calculator batteries and the led rating by putting two in series, but then if i have too much current flowing over them i'll get thermal runaway (because their resistance goes down with temperature increase) and they'll burn up, since i can't fit a resistor in there without lowering the voltage too much.
alternately, i can use 1 led and a resistor (which i calculated to be 96 ohms, or the closest standard size)
The single-led solution seems best, but i don't know if one will be enough to light up the screen very well. Would i have a significant decrease in light if i ran them at lower voltage?