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Re: Proving smallest surface area of cylinder is when h=2r
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Originally Posted by Joshua May
I think you've got it so far.
I believe the next step to go is to find the derivative of A=2(pi)(r^2) + 2V/r, set that to zero, solve it, and do a sign test to show that this is a minimum point.
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I thought that's what I do, but I'm not sure how to solve it. Please help, final is tomorrow morning!
Here's what I get for the derivative:
A'=4(pi)(r) +[(2r-2v)/(r^2)]
Is this right? If so, how do I solve it.
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Teacher/Engineer/Machinist - Team 696 Circuit Breakers, 2011 - Present
Mentor/Engineer/Machinist, Team 968 RAWC, 2007-2010
Technical Mentor, Team 696 Circuit Breakers, 2005-2007
Student Mechanical Leader and Driver, Team 696 Circuit Breakers, 2002-2004
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