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Re: Proving smallest surface area of cylinder is when h=2r
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Originally Posted by Greg Marra
Perhaps I'm missing something really obvious here, but...
Wouldn't the smallest surface area occur when h and r are as close to 0 as possible?
I mean, are we talking about in relation to something? In finite terms it'd seem that you can get a smaller surface area when you reduce either of those numbers...
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we're talking about for a fixed volume. so you can't vary things at will.
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