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How wide is the river?
I'm trying to solve this problem. http://home.att.net/~numericana/answ...onal.htm#ferry I understand most of it except for one thing. With the equation method of solving, how is it valid to divide the two equations? I know you are trying to eliminate the speed variable but I have never heard of that method (dividing equations) of solving before. Can someone please explain why that works?
And for the part below in blue text, I don't understand this part
Quote:
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The boat which had travelled 720 yd at the first meeting has therefore travelled three times that (2160 yd) at the second meeting.
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Can someone represent this graphically for me?
I have spent over two hours on this and I just can't understand. Please help.
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Teacher/Engineer/Machinist - Team 696 Circuit Breakers, 2011 - Present
Mentor/Engineer/Machinist, Team 968 RAWC, 2007-2010
Technical Mentor, Team 696 Circuit Breakers, 2005-2007
Student Mechanical Leader and Driver, Team 696 Circuit Breakers, 2002-2004
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