Quote:
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Originally Posted by gwross
You have to be careful that you're not dividing by zero, though. (Which would happen in the above example if w = -b or if 2w = b.)
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Good point. However, since the above example had
(w+b) / u = (2w-b) / v, dividing by zero would require both
w = -b and 2w = b. That's only possible if
w and
b are both equal to zero.
Since the original problem had nonzero values for both
a and
b, we know that we're not dividing by zero.