Thread: Calculus Query
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Unread 17-10-2005, 01:07
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Re: Calculus Query

Quote:
Originally Posted by David Guzman
I might be wrong but:

f(x)=1
f'(x)=0
f(x)^-1=0/1=0
EDIT:
If you're considering the reciprocal, then 1/1 is not equal to 0.
If you're considering the inverse function, then I didn't understand what you tried to do.

f(x)^-1 is a poor notation because it usually refers to the inverse of a function but can also be mistaken for the reciprocal of the function.
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Last edited by Manoel : 17-10-2005 at 01:40. Reason: Correction and clarification
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