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Re: coins in a dark room
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Originally Posted by KenWittlief
I think I reasoned it out, I had the right idea on my first post, but the wrong number
the original piles has 32 heads up, so you take 32 from the pile and flip them over. That is your second pile.
If you grabbed all 32 heads then there are no heads left in either pile
if you grabbed 18 heads and 18 tales, then you left 18 heads in the first pile, and when you flip the second pile you have 18 heads in both piles
if you grabbed 19 heads and 17 tales, then you left 17 heads in the first pile, and when you flip the second you have 17 heads and 19 tails
it works for all combinations
but I like the pocket answer better :^)
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Ken,
Last time I checked, 18+18=36 not 32.
Mike
__________________
Mike Betts
Alumnus, Team 3518, Panthrobots, 2011
Alumnus, Team 177, Bobcat Robotics, 1995 - 2010
LRI, Connecticut Regional, 2007-2010
LRI, WPI Regional, 2009 - 2010
RI, South Florida Regional, 2012 - 2013
As easy as 355/113...
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