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Re: Finding smallest forces required to produce a given moment
The Given Moment at P is Mp = 10 lb-ft.
a) Corners A and D are 10” apart = 0.833 ft.
The equivalent moment is Force X Distance = Fad X 0.833 ft = 10 lb-ft.
So, smallest F = 10 lb-ft/0.833 ft. = 12 lb, applied perpendicularly to side AD.
b) Corners B and C are 11.66 inches apart = 0.97 ft.
The equivalent moment is Fbc X 0.97 ft = 10 lb-ft
So, smallest Fbc = 10/0.97 = 10.3 lb., applied perpendicularly to side BC.
c) The greatest distance between two points on the block is from A to C, 18.867 inches = 1.572 ft.
The equivalent moment is Fac X 1.572 ft = 10 lb-ft
So smallest Fac = 10/1.572 = 6.36 lb, applied perpendicularly to the line AC.
Hope this helps and is in time for you - dashed it off quickly this AM - have to run.
Good luck.
__________________
Leo M.
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