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Originally Posted by KenWittlief
The answer most certainly can be determined by the laws of physics.
All planes move by reacting with the air, either trough propellers or jet engines. The speed of the ground under the wheels has almost nothing to do with the speed of the plane down the runway.
In this case, the plane would accelerate down the runway, and the 'runway' would accelerate in the other direction. The plane would still take off more or less normally, the only effect being the wheels will be spinning twice as fast as they normally would when it leaves the ground.
Hey that was easy, we settled the argument on CD in one post! :^)
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yes.... except one thing.
This conveyer has a control system that tracks the plane speed and tunes the speed of the conveyer to be
exactly the same (but in the opposite direction).
so. laws of wear and tear and motor output of either engine(plane or conveyor) ignored, but friction not ignored, the conveyor belt spins fast enough that the friction of the wheel bearings keep the plane from accelerating. so if the conveyor really can turn exactly the same speed(but in the opposite direction) of the plane, the plane would not be accelerating. relative to the conveyor belt it may as well be going almost the speed of light but since the conveyor belt is going the opposite way at almst the speed of light, the plane doesnt move.... im redundant arent i?
well anyways. so the plane wont fly then? i unno
but my thoughts are that a conveyor belt would fail before an airplane engine or landing gear so the plane would fly... eventually... but only after the conveyor belt fails.
-edit- addition-..... oh. and i should just say this.. you both completely ignored the way the conveyor belt works. its not a normal treadmill you see...