Quote:
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Originally Posted by Ashley Christine
Is this an answer, will this number solve everything for the year? Or is it all just coincidental : ponders :
Post your thoughts, or even YOUR 42's  |
That is amazing!
But I found one:
4^
2-(
4+
2) is the number of balls that can start on your robot in autonomous.
That's all I have. Ashley's crazy analysis took almost everything I can think of...
EDIT: I swear I remember typing in those parenthesis's.
