Quote:
|
Originally Posted by Joel J.
Yes, it samples faster than the rate the data is being sent.
I have another question for Kevin (of course, I'm trying to optimize everything, but I don't want to make a bad move while doing this):
Is there a specific reason for switching from doing both the initiation of and saving of an ADC sample in the timer interrupt? I remember in last year's gyro code that both functions were done in the same place, whereas now you are using both the timer interrupt, and the ADC interrupt to take the samples. Is it safe to kinda shift the ADC functionality to the timer interrupt and reduce the extra overhead by removing the ADC interrupt altogether? Or do the two of them together execute faster, somehow, than the single timer?
Before you:
- Started the initial A/D conversion in Initialize_XXXX()
- Saved the value at the start of the timer2 interrupt
- Did the if/else/etc to put the value in the right place
- Started another A/D conversion by setting the GO bit.
- Exited the timer2 interrupt.
And if I get the go ahead, I'll just do this again.
|
As I was waiting for your reply I took a look at the spec sheet for the PIC18f8722. It says there is a set delay of at least 2.5 microseconds that has to exist between the setting of an analog channel and the initiation of its conversion (to allow the sample and hold capacitor to start charging). Is this the reason for the seperation of the two actions?
I also see the following:
Quote:
|
Acquisition time may be set with the ACQT2:ACQT0 bits (ADCON2<5:3>) which provides a range of 2 to 20 TAD. When the GO/DONE bit is set, the A/D module continues to sample the input for the selected acquisition time, then automatically begins a conversion. Since the acquisition time is programmed, there may be no need to wait for an acquisition time between selecting a channel and setting the GO/DONE bit.
|
which makes it seem as though the PIC could implement a delay by itself. But taking another look at your code, I noticed that you enabled manual acquisition (ADCON2<5:3> = 0). Did you find the PIC to be unreliable in this area, or have I totally missed the point?
I'll wait for your feedback before continuing.