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Originally Posted by Richard
and a few more batteries. A rough estimate goes like this: to accelerate a 120# 'foolhardy payload' to 40 MPH exit velocity at 13 ft launcher height would require about 500 lbf thrust for about half a second. Assuming 50% conversion efficiency from the battery, you'd need about 40 kW electrical power during that split-second. Since our 12V batteries can only deliver about 200 peak amperes, you'd need about 16 of them to do the job.
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Nah, it works on compressed air. They'd just have to tweak the pnumatics rules.