Quote:
Originally Posted by jgannon
The square is the bounding box, the rectangle is the robot. The diagonal of the box is 72√2, the length of the robot is 38, and the wasted part of the diagonal in the lower left is 14. As such, I calculate that an object of negligible width can protrude (72√2)-38-14 = 49.8 inches from the front of a standard size robot. Is this consistent with our current interpretation? Does this make sense in the spirit of the rule?
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that reminds me of the joke about the boy with the fishing pole trying to get on the bus. The bus driver said his five foot fishing pole was too long, you can only have something four feet long on the bus. So, the boy visited the garbage cans behind some stores and found a 3 foot by 4 foot box and put the fishing pole in it, and was let on the bus.