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Re: 2 Cmucams?
Technically, he is right. in an UART, each byte is 10 bits (1 start, 8 data, 1 stop). running at 115200 continuously gives 115200/ 10 * 2 interrupts / second for the recievers alone.
Of course, the PIC can handle that, considering that the cameras will not continuously send data, however, a few thousand interrupts per second will be generated.
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