View Single Post
  #3   Spotlight this post!  
Unread 18-03-2007, 00:06
MrForbes's Avatar
MrForbes MrForbes is offline
Registered User
AKA: Jim
FRC #1726 (N.E.R.D.S.)
Team Role: Mentor
 
Join Date: Feb 2006
Rookie Year: 2006
Location: Sierra Vista AZ
Posts: 6,012
MrForbes has a reputation beyond reputeMrForbes has a reputation beyond reputeMrForbes has a reputation beyond reputeMrForbes has a reputation beyond reputeMrForbes has a reputation beyond reputeMrForbes has a reputation beyond reputeMrForbes has a reputation beyond reputeMrForbes has a reputation beyond reputeMrForbes has a reputation beyond reputeMrForbes has a reputation beyond reputeMrForbes has a reputation beyond repute
Re: Interpreting motor data

The RPM the motor will turn depends on how much voltage you supply to it. However, it also depends on how much load is applied to the motor...and the current the motor draws (amps) is also related to how much load is applied.

Also, the motor will work best if you keep the load to about 20% of the maximum (stall) torque, and the voltage to about 80% of the maximum voltage. So if the motor can produce 350 oz-in torque at stall, you would try to limit the load to 70 oz-in or less. If the RPM at maximum voltage is 5300, you would want to run the motor at about 4300 rpm (or less).

To calculate the maximum torque you can get from the motor at it's design conditions, multiply the torque times the transmission ratio. So if you have a 10:1 transmission, you would get 70 x 10 = 700 oz-in torque. Also if you are running the motor at 4300 rpm, the transmission would reduce that by a factor of 10, so the output shaft would turn at 430 rpm.

If you would give us some hints about what you are trying to do with the motor, we might be able to provide some more useful information.

Last edited by MrForbes : 18-03-2007 at 00:10.