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Re: Does Anyone Know The Answer????
Posted by Jerry Eckert, Engineer on team #140 from Tyngsboro, MA High School and New England Prototype/Brooks Automation.
Posted on 3/30/99 7:37 AM MST
In Reply to: Re: Does Anyone Know The Answer???? posted by Mike Kulibaba on 3/29/99 9:17 PM MST:
: : I think this is a good formula, I just want to know what happens if there are
: : two stages 8 teams, that changes it, and if we are surprised by a third stage
: : 12 teams on a once theoretically!
: I'll use random numbers for how many teams cause I'm not exactly sure how many teams are coming.
: Well let's say there are 224 teams we'll divide that by 8 for the 8 teams that go at one time.(26) then take that number and times it by 4 for the number of quilifying matches and you get 104 total qualifying matches! If there are 3 arenas(12 teams)and 228 teams, take 228 and divide it by 12 becaue ther are 12 teams going on at once(19)and then times that by 4 and you get 76 matches. I can go on if there are 4 stages but that isn't much of a possibility.
While I had no part in scheduling the qualifying rounds, I believe
you're looking at the problem backwards. The number of qualifying
matches per team was probably dervived from the number of qualifying
matches which can be run given the resources available, not vice versa.
As an example:
At the Hartford regional there were 82 qualifying matches. Assuming
the same amount of time is available to run qualifying matches at Disney,
that the average time per match is identical, and that two matches are
run simultaneously (two stages), then there can be roughly 82*2=164
total qualifying matches. Assuming 224 teams participate (using the
same number as above), there can be 164/(224/4) = 2.93 matches per team.
If you desire more matches per team then you modify the input parameters.
For example, allow more time for qualifying matches, reduce the time/match
(e.g., by overlapping running of one match with scoring of the previous
match), or running more matches simultaneously.
- Jerry
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