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Originally Posted by Kevin Sevcik
The outputs of the IR board can sink 8.5mA when driven low, which is easily enough to counteract any pullup resistor.
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I didn't exactly understand that in the spec sheet--I'm obviously missing a few concepts electrically. You are saying that when the IR board drives its pins low, it won't have a problem with the resistors. It makes sense now that you've pointed it out...in pretty much the same words as the spec sheet.
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Admittedly, this would be a problem if the IR outputs went to High-Z when there wasn't a signal
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Curiosity drives me to ask this: What exactly is High-Z? Does that mean the pins would go to high resistance (seen it called impedance) instead of driving them to ground?
All right, I'll make the changes. I was hoping to be able to do something like that--I don't want to mess with configuration bits like that, because I don't want to change the function of other code that relies on the pullups.
Thanks for your expertise, because, obviously I just don't have it. Yet. And I'm not supposed to, being that I'm a high school senior...
Maybe someday. MI Tech, here I come...
JBot