|
Re: Problems with IR Board
Quote:
Originally Posted by squirrel
the board runs at 5 volts, not 12 volts, so 228 / 5 = 46 mA....
|
I was quoting the values directly from the users guide provided by FIRST. I agree the circuit past the regulator is run off 5 vdc, but the board it's self is powered by >7.2 vdc to 10 vdc. In the users guide it says that it "assumes" the board is powered by 12 vdc.
Either way, the load drawn by circuit when one LED is on should not exceed the ability of the regulator to power the circuit without failing.
If there is a problem with the circuit, FIRST will find it, maybe with the help of some of us, (Remember the Bane-Bot trannies from last year?) and suggest, provide or publish the solution.
__________________
CalGames 2009 Autonomous Champion Award winner
Sacramento 2010 Creativity in Design winner, Sacramento 2010 Quarter finalist
2011 Sacramento Finalist, 2011 Madtown Engineering Inspiration Award.
2012 Sacramento Semi-Finals, 2012 Sacramento Innovation in Control Award, 2012 SVR Judges Award.
2012 CalGames Autonomous Challenge Award winner ($$$).
2014 2X Rockwell Automation: Innovation in Control Award (CVR and SAC). Curie Division Gracious Professionalism Award.
2014 Capital City Classic Winner AND Runner Up. Madtown Throwdown: Runner up.
2015 Innovation in Control Award, Sacramento.
2016 Chezy Champs Finalist, 2016 MTTD Finalist
|