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Originally Posted by hipsterjr
I have been curious as to exactly how much force it would take to launch a ball 10 ft at a 60 degree angle. ( for about 7ft high and between 5 and 7 ft horizontal from overpass.) I think arms and lifts are going to be too slow.
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Take a look in your physics textbook for kinematics formulas. The math to solve these types of problems is quite simple and is a common part of the Physics 11 curriculum here in BC. My estimates are that to launch the ball six and a half feet (roughly 2m) requires an accelleration of 2g over a distance of 1m.
In other words if you have 20lbs of force behind the ball for about 40" you should be able to get it to go 6 1/2' straight up from the last point you contacted it. To account for your desired 60 degree angle, take a look at breaking a vector down into orthogonal vectors (ie, how much "up" and how much "over" you will need). These are actually quite useful formula for many types of questions and are not that difficult to use and understand.
Jason