[gnormhurst]

Instead of using a floating point constant like this:

foo = bar * 0.44;

you can do this:

foo = bar * 44 / 100;

Note that the following, with the divide operation first, is not the same, because integer division throws away any remainder:

foo = bar / 100 * 44; // BAD IDEA!

Even better (if bar is always positive) you could do this:

foo = (bar * 113) >> 8;

The " >> 8 " divides the result by 256 (shifts the bits to the right eight places). The value 113 is .44 times 256. Be sure to use an int type for bar (16 bits), not a char type (8 bits); The shift operator " >> " behaves unpredictably for negative numbers.