[Gary Dillard]

Originally Posted by Swampdude

The clippard (model AVT-32-16) tanks hold 16 cu in (cubic inches) and each piston you want to use has an extended volume of 75 cu in. The clippards can be pressurized to 120psi (pounds per square inch).

Example: If you took 16 cu in (@1psi) and compressed it to 8 cu in, you would have 2 psi

So working backwards, if you contained 120 psi in (4) 16 cu in volumes, you would have 7680 cu in of air stored in the (4) clippards.

Now if you release that volume of air (7680 cu in) into (2) 24" pistons, and combine the (6) volumes (4 clippards and 2 pistons ) 16*4 + 75*2 = 214 cu in, or 7680/214 = 35psi

So (2) pistons connected to (4) clippards will fully extend with 109lbs of force and balance to 35psi.

That is only on the upstroke.

On the return, your tanks would then be at 35psi, or 2240 cu in
So 2240/214 = 10psi and 32lbs of force.

As far as dropping after the match, you can just let gravity do that and leave the top of your cylinders open.

Careful; see my post here describing how to do the calculations. pressure*volume calculations use absolute pressure, while force uses gage pressure. You don't get the same answer. taking 16 cu.in. of 1psig air (15.7 psia) gives you 8 cu.in of 31.4psia air, or 16.7 psig, not 2 psig.