[Al Skierkiewicz]

Hazmat,
A rule of thumb I use is called the Wire Foot. 100 amps flowing through a Wire Foot equals 0.1 volt drop across the wire. The wire foot is based on #10 wire which is 0.001 ohms per foot. 100 amps is near the stall current on a small CIM motor. #6 wire is 1/2WF per foot. Since all the robot current flows through the battery, main breaker and the wiring to the Rockwell block, losses can mount. You need to consider that all the current flowing in this part of the circuit is handled by both wires, red and black. So, if the battery can deliver 600 amps (yes that is what it is capable of, fully charged) and you place three feet of #6 wire in series with the battery you have introduced 6 x 0.5WF x 6 (100 amp) you have the potential for 1.8 volts to be dropped in just the #6 wires. So here are some other WF equivalents to think about.
Battery=11WF
Victor=6WF
#12=1.7WF/ft.
#14=2.5WF/ft.
Bad crimps=2-5WF/each
The critical issue in any robot design is making sure you can play the entire match. When the voltage supplied to the RC falls below 8 volts for a short period of time the RC goes into sleep mode and disables the PWM outputs. Protecting the RC should be a prime consideration in you electrical layout. Inches of wire could mean the difference in a critical score at the end of a match when the battery is low.