|
Re: Cim/planetary gearbox torque??
It should be the motor torque times the gear ratio. For example, if the motor puts out 80 Oz-In torque at 20% load, and your gearbox is 10:1 reduction, then it will give a final torque of 800 Oz-In. Less gearbox losses, of course...which will reduce it by about 15% as a guess.
|