Posted by bill whitley at 1/7/2001 10:09 PM EST
Student on team #70, Auto City Bandits, from Powers Catholic High School and Kettering University.
In Reply to: Re: size of see saw?
Posted by Ryan on 1/7/2001 9:26 PM EST:
If the hypotenuse is 8', and the opposite side is 2', then the height at the midpoint is exaclty 1'. No trig necessary. You can just use similar trianges.
: : The sizes of 8' x 4' for the see saw ramp is on the drawing but the hight is not. there is 2" angle 6" apart but no sizes for the hight from the floor to the top flat surface of the ramp carpet when level.
: : can anyone help??? and where did you see the answer.
: : nick237
: if you do some trigonemtery, i believe at the exact midpoint of the see-saw it will be approximately 11.9" aboe the ground. Try it, im probabbly wrong. Use 92" (8') as the hypotenuse, and 24" (2') as the vertical leg of the big triangle. Using trig you get the angle of the large triangle, and the horizontal leg. Divide 92" by 2 to get the midpoint, or the vertex of your smaller triangle (this is the point directly above the ground). Using the same angle, i got 11.9" as my vertical leg. I'm probablly wrong. Oh well another wasted year of highschool math.
: -Rc