[Bomberofdoom]

Originally Posted by Alan Anderson

// DISCLAIMER: THIS CODE IS UNTESTED

// declare some variables at the beginning of the code
char incount = 0; // this will count the input values being accumulated
int accumulator = 0; // this will accumulate input values
char smooth = 128; // this will hold the smoothed input value

// ....

// do this each time a new OI value is available
  accumulator += (int)potval; // replace 'potval' as appropriate, e.g. p1_aux
  if( incount++ == 8 ) // is this the eighth sample?
  {
    smooth = accumulator << 3; // a quick and sneaky way to divide by 8
    incount = 0; // set to count another eight samples
    accumulator = 0; // reset accumulator
  }

Does the incount++ action actually happen? I mean, when you check if the "if" statment is true, does the Microprocessor increase the valuce of incount? If it doesn't work, this should be done in a for loop, but if this "if" statment counts as a loop, then OK (it's just a method of a loop i've never seen before ).