Thread: Trig
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Unread 23-06-2002, 23:14
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#0047 (ChiefDelphi)
  
Join Date: May 2001
Location: Pontiac, MI
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Re: Problem is...
Posted by Dan at 1/20/2001 1:07 PM EST


Other on team #247, da Bears, from Berkley High and PICO/Wisne Design.


In Reply to: Problem is...
Posted by Nick on 1/20/2001 6:33 AM EST:



You don't need to have the arctan function. It was mentioned just to help understand how the final answer was derived. It wasn't meant to be a line in your program.

I assume you want the sine and cosine of the angle whose tan is x/y. If you know x and y, the sine and cosine of that angle (which you'll never calculate) are:
sine = x/sqrt(x^2+y^2) and cosine = y/sqrt(x^2+y^2).

These are functions of x and y only, no angle.

Hope that helped.

-Dan
#247


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