Thread: Trig
View Single Post
  #5   Spotlight this post!  
Unread 23-06-2002, 23:14
archiver archiver is offline
Forum Archival System
#0047 (ChiefDelphi)
  
Join Date: May 2001
Location: Pontiac, MI
Posts: 21,214
archiver has a reputation beyond reputearchiver has a reputation beyond reputearchiver has a reputation beyond reputearchiver has a reputation beyond reputearchiver has a reputation beyond reputearchiver has a reputation beyond reputearchiver has a reputation beyond reputearchiver has a reputation beyond reputearchiver has a reputation beyond reputearchiver has a reputation beyond reputearchiver has a reputation beyond repute
Re: Trig
Posted by Dan at 1/19/2001 2:32 PM EST


Other on team #247, da Bears, from Berkley High and PICO/Wisne Design.


In Reply to: Trig
Posted by Nick on 1/19/2001 6:07 AM EST:



Pretty much the same as the last reply:

A (angle) = arctan(x/y)
tan A = x/y
Setting up a right triangle with x opposite A and y adjacent to A, hypotenuse becomes sqrt(x^2+y^2) and the rest follows:
sin A = x/sqrt(x^2+y^2) and cos A = y/sqrt(x^2+y^2)

This works fine if the angles you're dealing with are between 0 and 90. Is this true?

-Dan
#247


__________________
This message was archived from an earlier forum system. Some information may have been left out. Start new discussion in the current forums, and refer back to these threads when necessary.