[EricVanWyk]

Gustavo -

The answer is depends on if you intend to use the IFI system or the 2009 system.

I do not know the IFI answer, so I will not attempt to fabricate one.

For 2009, the minimum resistance of the potentiometers is dictated by current draw and heat dissipation. You may draw up to 750mA for one analog sensor* (3A total), which would limit you to about 7 ohms. However, this would dissipate about 4 Watts, which is probably not what you want.

At 22 Ohms, you will dissipate roughly a watt. Make sure that your potentiometer can handle it.

The maximum resistance is dictated by the input impedance of the NI9201 Analog Input Module. If your potentiometer's resistance is too high, the small current the 9201 draws to measure the voltage will impact the reading. Since I do not know the NI answer, I will not attempt to fabricate one.

Please note that my post only represents the capabilities of the system and do not reflect the robot rules. Robot rules may place additional limitations on the system.