Quote:
Originally Posted by rsisk
At the risk of looking like an EE neophyte, can you explain how amperage draw, the resistance (ohms) and the energy dissipated are related? There must be a formula for that.
Thanks
|
Sure, I used these to remember:
V = C R (even if it blinks 12:00 forever)
P = V C
V(olts) C(urrent) R(esistance) P(ower)
To do your calculation, I took:
Power = Voltage^2 / resistance
To double check, you can use the google calculator - It does units! Just google "(5V)^2/22 ohms"