View Single Post
  #79   Spotlight this post!  
Unread 05-01-2009, 21:40
EricH's Avatar
EricH EricH is offline
New year, new team
FRC #1197 (Torbots)
Team Role: Engineer
 
Join Date: Jan 2005
Rookie Year: 2003
Location: SoCal
Posts: 19,819
EricH has a reputation beyond reputeEricH has a reputation beyond reputeEricH has a reputation beyond reputeEricH has a reputation beyond reputeEricH has a reputation beyond reputeEricH has a reputation beyond reputeEricH has a reputation beyond reputeEricH has a reputation beyond reputeEricH has a reputation beyond reputeEricH has a reputation beyond reputeEricH has a reputation beyond repute
Re: Propulsion that does not involve driving wheels

Quote:
Originally Posted by comphappy View Post
Yes but that does nothing for your acceleration.

m*g*u=m*a
gu=a

So a robot that is 500lbs wheels will spinout like a robot that is 10lbs.
Collisions are a different story, and my thought on that will be left between me and my team for now.
F=m*a
Frictional force = mu*N, where N = m*g, where g= 9.8 m/s^2= the gravitational constant acceleration

You're saying that m*a=mu*m*g, right? m cancels out, leaving a=mu*g.

However, the g has been increased by using a fan or something to add downwards force! Guess what? a must increase!

And lbs are NOT a unit of mass, they are a unit of force, which is computed by m*g. Increase g and you increase the force.

Let's look at your scenario: 500 lbs=32f/s^2*x slugs (slug being the English system's unit of mass) 10 lbs =32 f/s^2*y slugs
you are saying that 32f/s^2 * x slugs = 32f/s^2 * y slugs. Cancel out 32f/s^2 and you get x slugs = y slugs. Cancel out the units and x = y. However, because 500/32 = x slugs and 10/32 = y slugs, you get 500/32=10/32, which simplifies to 500=10. This isn't true, is it?
__________________
Past teams:
2003-2007: FRC0330 BeachBots
2008: FRC1135 Shmoebotics
2012: FRC4046 Schroedinger's Dragons

"Rockets are tricky..."--Elon Musk